first shape look like this:

top bottom rest of shape extra piece

S.A.= 2 (lw) + Ph(perimeter-height)+ 2(lw)

=2(2)(3)+10(2)+2(1)(1)

=12+20+2

=34u^2

(information)

to find the perimeter of the rest of the piece is 3+2+3+2.

the extra piece that is not shown. It has two pieces that has a dimension of 1-1.

2nd shape:

large-small

top and bottom sides front back inside

S.A.= 2(lw) + 2(lw) +2(s2+s2) +4 (lw)

= 2(2)(3) + 2(2)(3) +2 (3^2-1^2)+4 (1)(2)

= 12+12+2(9-1) +8

= 48^2

3rd shape is a cylinder:

here is the net of the image:

Circumference= (pi.D)---->(2 pi r)

diameter of the circle is 10 and the height of the cylinder is 12.

S.A.=2 pi r^2 + 2 pi r h ( to find the radius you divide the diameter by 2)

=2 pi 5^2 + 2 pi (5)(12)

=2 pi 25 + 2 pi 60

=50 pi + 120 pi

= 170u^2 <------ solve in pi (accurate)

= 534.07 u^2 <------- solve to the hundredths (approximation)

HOMEWORK!! : Journal, all apply 1.3(22 or 23), all practice sheet , all workbook, Study for test( Tuesday or Wednesday)

Aj will be doing the next blog.