first shape look like this:
top bottom rest of shape extra piece
S.A.= 2 (lw) + Ph(perimeter-height)+ 2(lw)
=2(2)(3)+10(2)+2(1)(1)
=12+20+2
=34u^2
(information)
to find the perimeter of the rest of the piece is 3+2+3+2.
the extra piece that is not shown. It has two pieces that has a dimension of 1-1.
2nd shape:
large-small
top and bottom sides front back inside
S.A.= 2(lw) + 2(lw) +2(s2+s2) +4 (lw)
= 2(2)(3) + 2(2)(3) +2 (3^2-1^2)+4 (1)(2)
= 12+12+2(9-1) +8
= 48^2
3rd shape is a cylinder:
here is the net of the image:
Circumference= (pi.D)---->(2 pi r)
diameter of the circle is 10 and the height of the cylinder is 12.
S.A.=2 pi r^2 + 2 pi r h ( to find the radius you divide the diameter by 2)
=2 pi 5^2 + 2 pi (5)(12)
=2 pi 25 + 2 pi 60
=50 pi + 120 pi
= 170u^2 <------ solve in pi (accurate)
= 534.07 u^2 <------- solve to the hundredths (approximation)
HOMEWORK!! : Journal, all apply 1.3(22 or 23), all practice sheet , all workbook, Study for test( Tuesday or Wednesday)
Aj will be doing the next blog.
