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Sunday, November 20, 2011

Ivan's Math Question 2.4 #29

Question: The speed of sound in air, s, in metres per second, is related to the temperature, t, in degrees Celsius, by formula s =√(401(273+t) ). How much greater is the speed of sound on a day when the temperature is 30◦C than on a day when the temperature is -20◦C? Express your answer to the nearest metre per second.

Since there are two temperatures, you can find two s's.

So find 30◦C first.273+30=303
303x401 = 121503
√121503 = 348.57

Then you find the second one -20◦C.
273+ -20 = 253
253x401 = 101453
√101453 = 318.52

Then I did.
348.57 - 318.52 = 30.05

S.S: The speed of sound on a day when the temperature is 30 degrees C is greater by 30m/s than on a day when the temp. is -20 degrees C.

3 comments:

  1. Good job ivan you explained your work very well. Next time you should try putting some of the important words or numbers in different colours.

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  2. Good Job on your post Ivan. I liked how you explained how you got your answer well. I also liked the simple sentence at the end. But you could have added colour and even pictures!

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  3. Good job explaining your work but next time try adding pictures so we can understand it better. I liked how it was also neat but again, try adding some color to make things pop out. Overall, good job

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