Ishaka's Math Question

The question that I was given was #22 chapter 2.4

The question said: The hypotenuse of an isosceles right triangle has a length of 20 cm. What is the length of each leg of the triangle? Provide your answer to the nearest tenth of a centimetre.

First I drew out the isosceles right triangle in the question

Then I just answered the question using this formula:

The length of each leg of this triangle is 14.1 cm

Ishaka's Math Question

Question 13 in 2.3

The diameter of Pluto is 6/17 the diameter of Mars. Mars is 17/300 the diameter of Saturn.

a) What fraction of the diameter of Saturn is the diameter of Pluto
b) The diameter of Saturn is 120 000km. What is the diameter of Pluto?


To figure out these questions we would need to find out the diameter of Mars.

To do that you would have to multiply 17/300 by 120 000/1

Which would equal 2 040 000/300
Then you would have to divide 2 040 000/300 to get Mars' diameter.
Mars' diameter equals 6 800km

Now that we have found the diameter of Mars we can find the diameter of Pluto.
6/17 x 6 800/1 = 40 800/17

Then divide 40 800/17 to get 2 400km

Then just simplify 2 400/120 000 which is 1/50

Question a) = 1/50

Question b) Was answered already (2 400km)

Ishaka's Blog Post

During our math class on Friday we didn't do much because we had an evacuation drill, but we answered question 4 a) from page 32 with the enitre class.

Question a) was asking us to find the surface area of a 3D shape.


(Question 4 a) as a net)


STEP 1

We had to split the 2 sides into to parts because we didn't have a formula that would help us with that kind of shape.


STEP 2

After spliting the two sides into two parts, we started to label A1, A2, A3, and A4, for the parts that were the same to help us with the formula.


(There are 3 A2's because both the tops equal the base, and there are also 3 A1's because both the fronts equal the back.)

STEP 3

Now that we had all the information that we needed to find the surface area, we just filled in the information into our formula.

S.A = 2(A1) + 2(A2) + 2(A3) + 2(A4)
2(lw) + 2(lw) + 2(s^2) + 2(lw)
2(4.5) + 2(2.5) + 2(2^2) + 2(2.1)
40 + 20 + 8 + 4 = 72units^2

HOMEWORK: Page 32 #'s 4 - 9, and also write in your math journal.



John will be doing the next blog post.