Rise and Run

January 27, 2012's class

Chapter 6

In class we learned more about finding the equation of a graph using rise and run. We had many examples.

Now we know what m is, we can put that in our equation to find y.

y=mx+b

Remember the m is the slope or gradient and the b is the y intercept.

The m will be 4/7 and the b will be 1.

y=4/7x+1

We put the results in a table:

Here's how we got the y using the equation:

y=mx+b

=4/7x+1

= 4/7(1)+1 (you multiply 4/7 by 1)

=4/7+1 (you add 1 to 4/7)

=1 4/7

y=mx+b

=4/7x+1

=4/7(2)+1

=8/7=1 (simplify 8/7 to 1 1/7)

=1 1/7+1

=2 1/7

We also did a problem where b=0.

Since b=0, then in the equation there doesn't need to be +b. We used 1 and 14 for x.

y=mx

=2/3x

=2/3(1)

=2/3

y=mx

=2/3x

=2/3(14)

=28/3 (simplify 28/3 to 9 1/3)

=9 1/3

You call them by where they go through the line

Homework

Chapter 6.3

-all practice

-all apply

-try any 2 of extend

-Homework Book

-Save your Dumb Planet

-CYU question1 due monday

-MANGAHIGH!!

Glenesse's Math Question

My question is # 28 in chapter 2.4.

Question:

The period, t, in seconds, of a pendulum is the time for a complete swing back and forth. The period can be calculated from the length, l, in metres, of the pendulum using the formula t = √4l. Determine the period of a pendulum with each of the following lengths. Express each answer to the nearest hundredth of a second.

a) 1.6 m

b) 2.5 m
c) 50 cm

Answers:

a) The period of a pendulum with the length of 1.6 m is 2.53 (s) seconds.

I first multiplied the length, which was 1.6, by 4 and got 6.4. I then square rooted that and got 2.53 s.

b) The period of a pendulum with the length of 2.5 m is 3.16 (s) seconds.

I first multiplied the length, which is 2.5, by 4 and got 10. I then square rooted that and got 3.16 s.

c) The period of a pendulum with the length of 50 cm is 1.41 (s) seconds.

I first multiplied the length, which is 50, by 4 and got 200. I then square rooted that and got 14.14, but I had to divide that by ten because we need to get from cm to m. I then got 1.41 s.

Chapter 2.3: Question #16

Question:

Boris has 2 1/2 times as much cash as Anna. Charlie has 3/4 as much cash as Anna. Anna has $25.60 in cash.

a)How much cash do the three people have altogether?

b)How much more cash does Boris have than Charlie?

Answers:

a) The three people have $108.80 all together.

1) First I multiplied 2 1/2 by 25.6o.

2) Second I multiplied 3/4 by 25.60

3)Then for question a) I added how much Boris had, which was $64, then added how much Charlie had, which was $19.20, then lastly I added how much Anna had, which was $25.60.

b) Boris has $44.80 more than Charlie.

1) I used the answers i got from question a) for question b).

2) I subtracted what Charlie had, which was $19.20, from what Boris had, which was $64.